My code in Swift vs. Java. Swift gives an error but Java doesn't. Are there any differences?

So I'm writing an app that will find the prime factors of a number. I'm writing the app in Swift but it gives me an error if i set "num" to an even number but not an odd number. The error says, Execution was interrupted, reason: EXC_BAD_INSTRUCTION code=EXC_l386_INVOP, subcode=0x0 on the 5th line of code.

Here's the Swift code:

var num = 16

for i in 2...(num/2)-1 {

    if ((num % i) == 0) {
        var isPrimeFactor = true

        for l in 2...i-1 {
            if ((i%l) == 0) {
                isPrimeFactor = false;
            }//end if
        }//end for

        if (isPrimeFactor == true) {
            i
        }//end if

    }//end if

}//end for

Here's the Java code(that I thought was an exact copy of the Swift code):

int num = 16;

for (int i=2; i<num/2; i++) {
    if (num%i == 0) {
        boolean isPrimeFactor = true;

        for (int l=2; l<i; l++) {
            if ((i%l) == 0) {
                isPrimeFactor = false;
            }
        }

        if (isPrimeFactor == true) {
            System.out.println(i);
        }
    }
}

Also, did Apple get rid of the .. in for loops? I get an error using those too.